I am using the RasaNLUHttpInterpreter as stated here to start my server. I give the class all the 4 parameters required (model-name, token, server-name, and project-name). However, I always get the error, that apparently I am handing over 5 arguments (what I don’t really do). The error occurred since I updated my Rasa-Core and NLU to the latest version. However, as in docs, I feel that I use the method correctly. Does anyone have an idea what I am doing wrong or what’s happening here? Here is my run-server.py where I use the RasaNLUHttpInterpreter: import os from os import environ as env from gevent.pywsgi import WSGIServer from server import create_app from rasa_core import utils from rasa_core.interpreter import RasaNLUHttpInterpreter utils.configure_colored_logging("DEBUG") user_input_dir = "/app/nlu/" + env["RASA_NLU_PROJECT_NAME"] + "/user_input" if not os.path.exists(user_input_dir): os.makedirs(user_input_dir) nlu_interpreter = RasaNLUHttpInterpreter( 'model_20190702-103405', None, 'http://rasa-nlu:5000', 'test_project') app = create_app( model_directory = env["RASA_CORE_MODEL_PATH"], cors_origins="*", loglevel = "DEBUG", logfile = "./logs/rasa_core.log", interpreter = nlu_interpreter) http_server = WSGIServer(('0.0.0.0', 5005), app) http_server.serve_forever() I am using: rasa_nlu~=0.15.1 rasa_core==0.14.5

RasaNLUHttpInterpreter: takes from 1 to 4 positional arguments but 5 were given

MetcalfeTom (Thomas Metcalfe) July 17, 2019, 8:02am 21

@JulianGerhard If you could post something that would be great

Topic		Replies	Views
$ rasa run # triggers argparse error for nlu model Rasa Open Source	2	564	October 1, 2020
Rasa NLU parameter parsing Rasa Open Source	10	1548	March 25, 2020
Parse a message with the trained nlu model Rasa Open Source	1	3937	July 3, 2019
Rasa_nlu.server cannot load model? Rasa Open Source	4	2626	December 4, 2018
Using RASA NLU with python code and without API Rasa Open Source	5	1492	August 17, 2023