Looking for help in implementing Custom Channel

Getting Started with Rasa
1

Hi,

I’m trying to implement a custom connector for our internal messenger.

As per the Custom Connectors Guide, I created a python script in my application directory chatbotchannel.py and implemented InputChannel class.

#filename : chatbotchannel.py
class ChatBot(InputChannel):
    @classmethod
    def name(cls):
        return "chatbot"

Also added below entry in the credentials.yml file in the app directory (this dir is created using rasa init)

# filename : credentials.yml
# This file contains the credentials for the voice & chat platforms
# which your bot is using.
# https://rasa.com/docs/rasa/user-guide/messaging-and-voice-channels/

rest:
#  # you don't need to provide anything here - this channel doesn't
#  # require any credentials

#entry for custom channel
chatbotchannel.ChatBot:

I get below error when I start the server using rasa run command.

Traceback (most recent call last):
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/core/run.py", line 50, in _create_single_channel
    input_channel_class = class_from_module_path(channel)
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/utils/common.py", line 188, in class_from_module_path
    m = importlib.import_module(module_name)
  File ".direnv/python-3.7.3/lib/python3.7/importlib/__init__.py", line 127, in import_module
    return _bootstrap._gcd_import(name[level:], package, level)
  File "<frozen importlib._bootstrap>", line 1006, in _gcd_import
  File "<frozen importlib._bootstrap>", line 983, in _find_and_load
  File "<frozen importlib._bootstrap>", line 965, in _find_and_load_unlocked
ModuleNotFoundError: No module named 'chatbotchannel'


During handling of the above exception, another exception occurred:

Traceback (most recent call last):
  File ".direnv/python-3.7.3/bin/rasa", line 10, in <module>
    sys.exit(main())
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/__main__.py", line 70, in main
    cmdline_arguments.func(cmdline_arguments)
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/cli/run.py", line 101, in run
    rasa.run(**vars(args))
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/run.py", line 59, in run
    **kwargs
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/core/run.py", line 138, in serve_application
    input_channels = create_http_input_channels(channel, credentials)
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/core/run.py", line 37, in create_http_input_channels
    return [_create_single_channel(c, k) for c, k in all_credentials.items()]
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/core/run.py", line 37, in <listcomp>
    return [_create_single_channel(c, k) for c, k in all_credentials.items()]
  File ".direnv/python-3.7.3/lib/python3.7/site-packages/rasa/core/run.py", line 58, in _create_single_channel
    "is a proper name of a class in a module.".format(channel)
Exception: Failed to find input channel class for 'chatbotchannel.ChatBot'. Unknown input channel. Check your credentials configuration to make sure the mentioned channel is not misspelled. If you are creating your own channel, make sure it is a proper name of a class in a module.

What should be the correct format in credentials.yml file to declare my custom channel python script and class?

2

any help is appreciated.

Thanks

3

Hi @harryharanb, did you end up solving this issue?

4

not yet. I created python module for custom channel, but having difficulty in calling that module via rasa run command with details added in credentials file.

5

Do you succeed ?

6

hey @harryharanb, make sure the custom channel module is withing your project directory.

7

I am having this issue too, did anyone solve this issue? any help is appreciated.

8

Hello

Please read the thread on forum here :