I am using the RasaNLUHttpInterpreter as stated here to start my server. I give the class all the 4 parameters required (model-name, token, server-name, and project-name). However, I always get the error, that apparently I am handing over 5 arguments (what I don’t really do). The error occurred since I updated my Rasa-Core and NLU to the latest version. However, as in docs, I feel that I use the method correctly. Does anyone have an idea what I am doing wrong or what’s happening here? Here is my run-server.py where I use the RasaNLUHttpInterpreter: import os from os import environ as env from gevent.pywsgi import WSGIServer from server import create_app from rasa_core import utils from rasa_core.interpreter import RasaNLUHttpInterpreter utils.configure_colored_logging("DEBUG") user_input_dir = "/app/nlu/" + env["RASA_NLU_PROJECT_NAME"] + "/user_input" if not os.path.exists(user_input_dir): os.makedirs(user_input_dir) nlu_interpreter = RasaNLUHttpInterpreter( 'model_20190702-103405', None, 'http://rasa-nlu:5000', 'test_project') app = create_app( model_directory = env["RASA_CORE_MODEL_PATH"], cors_origins="*", loglevel = "DEBUG", logfile = "./logs/rasa_core.log", interpreter = nlu_interpreter) http_server = WSGIServer(('0.0.0.0', 5005), app) http_server.serve_forever() I am using: rasa_nlu~=0.15.1 rasa_core==0.14.5

RasaNLUHttpInterpreter: takes from 1 to 4 positional arguments but 5 were given

Ahmed (Kharroubi) July 2, 2019, 11:55am 2

Hello @threxx can you show me the error you’re getting when you launch your server ?

NLU Data: add placeholders to nlu data

Topic		Replies	Views
Rasanluinterpreter loading import error Rasa Open Source	1	627	July 30, 2019
Rasa NLU parameter parsing Rasa Open Source	10	1421	March 25, 2020
Python API for NLU interpreter and Agent Rasa Open Source	1	1550	December 22, 2019
Rasa_nlu.server cannot load model? Rasa Open Source	4	2523	December 4, 2018
Getting an error while i run nlu_model.py Rasa Open Source	1	1784	August 27, 2019